36x^2+76x+8=0

Solution for 36x^2+76x+8=0 equation:

36x^2+76x+8=0

a = 36; b = 76; c = +8;
Δ = b2-4ac
Δ = 762-4·36·8
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-68}{2*36}=\frac{-144}{72}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+68}{2*36}=\frac{-8}{72}
=-1/9
$